Question 1 of 5: Match the graph to its function:
![graphing ([x^2] / [36]) + ([y^2] / [49])=1](../../img.2018/College_Algebra/154/EllipseT1.svg)
Select the Correct Answer: Correct! 
Not Correct! 
Not Correct! A
$$\frac{x^2}{49}+ \frac{y^2}{36}=1$$
B
$$\frac{(x - 6)^2}{36}+ \frac{(y - 7)^2}{49}=1$$
C
$$\frac{x^2}{25}+ \frac{y^2}{64}=1$$
D
$$\frac{(x - 1)^2}{36}+ \frac{(y - 3)^2}{49}=1$$
E
$$\frac{x^2}{36}+ \frac{y^2}{49}=1$$
Question 2 of 5: Match the graph to its function:
Select the Correct Answer: Correct! Not Correct!
Not Correct! A
$$9x^2 + y^2 + 36x=0$$
B
$$5x^2 + y^2 - 8x - 4y + 7=0$$
C
$$3x^2 + 2y^2 + 6x + 5y + 1=0$$
D
$$x^2 + 2y^2 + 3x - 12y + 1=0$$
E
$$-4x^2 - 3y^2 + 2x + 5y + 2=0$$
Question 3 of 5: Write the equation in standard form:
Select the Correct Answer: Correct! Not Correct!
Not Correct! A
$$\frac{(x + 2)^2}{25}+ \frac{(y + 5)^2}{9}=1$$
B
$$\frac{(x - 5)^2}{25}+ \frac{(y - 2)^2}{9}=1$$
C
$$\frac{(x + 5)^2}{25}+ \frac{(y + 2)^2}{9}=1$$
D
$$\frac{x^2}{25}+ \frac{y^2}{9}=1$$
E
$$\frac{(x + 5)^2}{5}+ \frac{(y + 2)^2}{3}=1$$
Question 4 of 5: Write the equation in standard form:
Select the Correct Answer: Correct! Not Correct!
Not Correct! A
$$\frac{(x - 2)^2}{12}+ \frac{(y - 5)^2}{19}=1$$
B
$$\frac{(x + 5)^2}{144}+ \frac{(y + 7)^2}{169}=1$$
C
$$\frac{(x - 5)^2}{12}+ \frac{(y - 3)^2}{16}=1$$
D
$$\frac{x^2}{12}+ \frac{y^2}{13}=1$$
E
$$\frac{x^2}{13}+ \frac{y^2}{12}=1$$
Question 5 of 5: Write the equation in standard form:
Select the Correct Answer: Correct! Not Correct!
Not Correct! A
$$\frac{(x - 2)^2}{16}+ \frac{(y - 9)^2}{25}=1$$
B
$$\frac{(x + 2)^2}{16}+ \frac{(y + 9)^2}{25}=1$$
C
$$\frac{(x + 2)^2}{4}+ \frac{(y + 9)^2}{5}=1$$
D
$$\frac{x^2}{4}+ \frac{y^2}{5}=1$$
E
$$\frac{(x + 9)^2}{16}+ \frac{(y - 2)^2}{25}=1$$
