About Domain and Range:
When working with relations and functions, we will sometimes be asked to find the domain and range of a relation or function from its equation or its graph. If we want to find the domain, we will inspect our equation and ask the question: what is allowed as a replacement for our independent variable x? For the range, we will think about the possible outputs or y-values, given the possible x-values.
Test Objectives
- Demonstrate the ability to find the domain and range of a relation or function from a graph
- Demonstrate the ability to find the domain of a relation or function
#1:
Instructions: find the domain and range.
$$a)\hspace{.2em}y=-3x - 2$$
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#2:
Instructions: find the domain and range.
$$a)\hspace{.2em}y=\sqrt{x + 1}- 3$$
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#3:
Instructions: find the domain.
$$a)\hspace{.2em}y=-\frac{7}{x^2 - 4x - 5}$$
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#4:
Instructions: find the domain.
$$a)\hspace{.2em}y=\frac{\sqrt{3x - 2}}{6x^2 + 8x - 30}$$
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#5:
Instructions: find the domain.
$$a)\hspace{.2em}y=\frac{\sqrt{35x^2 - 58x - 9}}{\sqrt{x^2 - 2x + 1}}$$
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Written Solutions:
#1:
Solutions:
$$a)\hspace{.2em}Domain: \{x|x \in \mathbb{R}\}$$ $$Range: \{y|y \in \mathbb{R}\}$$
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#2:
Solutions:
$$a)\hspace{.2em}Domain: \{x|x≥ -1\}$$ $$Range: \{y|y ≥ -3\}$$
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#3:
Solutions:
$$a)\hspace{.2em}Domain: \{x | x ≠ -1, 5\}$$
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#4:
Solutions:
$$a)\hspace{.2em}Domain: \left\{x | x ≥ \frac{2}{3}, x ≠ \frac{5}{3}\right\}$$
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#5:
Solutions:
$$a)\hspace{.2em}Domain: \left\{x | x ≤ -\frac{1}{7}, x ≥ \frac{9}{5}\right\}$$
