### About Solving Exponential Equations with Logarithms:

When we work with exponential equations, we have an easy case, where we can find our solution without the use of logarithms. This happens when we have the same base on each side of the equation. The harder case occurs when we can't write each side with the same base. For this scenario, we turn to logarithms and our power property to obtain a solution.

Test Objectives
• Demonstrate an understanding of the properties of logarithms
• Demonstrate the ability to solve an exponential equation using logarithms
Solving Exponential Equations with Logarithms Practice Test:

#1:

Instructions: solve each equation.

$$a)\hspace{.2em}18^{6x}+ 6=60$$

#2:

Instructions: solve each equation.

$$a)\hspace{.2em}2 \cdot 20^{-6x - 9}- 7=19$$

#3:

Instructions: solve each equation.

$$a)\hspace{.2em}9^{x - 1}=3^{x + 4}$$

#4:

Instructions: solve each equation.

$$a)\hspace{.2em}e^{5x - 1}\cdot e^{2x}=7e$$

#5:

Instructions: solve each equation.

a) If money is invested in a CD that is compounded continuously at 1.9% annual interest, how long will it take for the investment to double in value?
Continous Compound Interest Formula: $$A=Pe^{rt}$$

Written Solutions:

#1:

Solutions:

$$a)\hspace{.2em}x=\frac{log(54)}{6log(18)}\approx 0.23$$

#2:

Solutions:

$$a)\hspace{.2em}x=-\frac{3}{2}- \frac{log(13)}{6log(20)}\approx -1.6427$$

#3:

Solutions:

$$a)\hspace{.2em}x=6$$

#4:

Solutions:

$$a)\hspace{.2em}x=\frac{ln(7) + 2}{7}\approx 0.5637$$

#5:

Solutions: