Lesson Objectives

- Demonstrate an understanding of logarithms
- Learn how to use the product rule for logarithms
- Learn how to use the quotient rule for logarithms
- Learn how to use the power rule for logarithms
- Learn how to write alternative forms of logarithmic expressions

## Properties of Logarithms

In the last lesson, we introduced the concept of a logarithm. In this lesson,
we will go deeper into the topic of logarithms. Let's begin by learning about the product rule for logarithms.

log

Let's take a look at a few examples.

Example 1: Expand each logarithm

log

Using the product rule for logarithms, we can expand our logarithm:

log

Example 2: Condense each expression into a single logarithm

log

We can use the product rule for logarithms to condense our expression into a single logarithm.

log

Example 3: Expand each logarithm $$log_{12}\left(\frac{11}{5}\right)$$ Using the quotient rule for logarithms, we can expand our logarithm: $$log_{12}\left(\frac{11}{5}\right) = log_{12}(11) - log_{12}(5)$$ Example 4: Condense each expression into a single logarithm. $$log_{8}(x) - log_{8}(z)$$ We can use the quotient rule for logarithms to condense our expression into a single logarithm. $$log_{8}(x) - log_{8}(z) = log_{8}\left(\frac{x}{z}\right)$$

log

This rule allows us to take the power out of the argument. It will be multiplied by the logarithm. In other words, the logarithm of a number which is raised to a power is equal to the power multiplied by the logarithm of the number. Let's look at an example.

Example 5: Use the power rule to rewrite each logarithm

log

Using the power rule for logarithms, we can rewrite our logarithm:

log

If b > 0 and b ≠ 1, then:

b

log

Let's look at a few examples.

Example 6: Evaluate each

log

Using our above rules, we can evaluate our problem as:

log

Example 7: Evaluate each

10

Using our above rules, we can evaluate our problem as:

10

Example 8: Expand each logarithm

log

Let's start by moving the exponent of 5 out in front of the logarithm:

5log

Now, let's use our product rule for logarithms to expand:

5log

Lastly, we can move the exponent of 3 out in front:

(3 • 5)log

15log

Example 9: Condense each expression into a single logarithm $$log_{5}(z) + \frac{log_{5}(x)}{2} + \frac{log_{5}(y)}{2}$$ Let's rewrite division by 2 as multiplication by 1/2: $$log_{5}(z) + \frac{1}{2}log_{5}(x) + \frac{1}{2}log_{5}(y)$$ Using the power rule for logarithms, we can rewrite our problem as: $$log_{5}(z) + log_{5}(x^{ \frac{1}{2}}) + log_{5}(y^{\frac{1}{2}})$$ When we raise a number to the power of 1/2, this is the same as taking the square root of the number: $$log_{5}(z) + log_{5}(\sqrt{x}) + log_{5}(\sqrt{y})$$ Now, we can wrap up the problem by using our product rule for logarithms: $$log_{5}(z\sqrt{xy})$$

### Product Rule for Logarithms

If x, y, and b are positive real numbers, where b ≠ 1, then:log

_{b}(xy) = log_{b}(x) + log_{b}(y)Let's take a look at a few examples.

Example 1: Expand each logarithm

log

_{10}(3y)Using the product rule for logarithms, we can expand our logarithm:

log

_{10}(3y) = log_{10}(3) + log_{10}(y)Example 2: Condense each expression into a single logarithm

log

_{7}(5) + log_{7}(3)We can use the product rule for logarithms to condense our expression into a single logarithm.

log

_{7}(5) + log_{7}(3) = log_{7}(5 • 3) = log_{7}(15)### Quotient Rule for Logarithms

In addition to the product rule for logarithms, we also have a quotient rule for logarithms. If x, y, and b are positive real numbers, where b ≠ 1, then: $$log_{b}\left(\frac{x}{y}\right) = log_{b}(x) - log_{b}(y)$$ Let's look at a few examples.Example 3: Expand each logarithm $$log_{12}\left(\frac{11}{5}\right)$$ Using the quotient rule for logarithms, we can expand our logarithm: $$log_{12}\left(\frac{11}{5}\right) = log_{12}(11) - log_{12}(5)$$ Example 4: Condense each expression into a single logarithm. $$log_{8}(x) - log_{8}(z)$$ We can use the quotient rule for logarithms to condense our expression into a single logarithm. $$log_{8}(x) - log_{8}(z) = log_{8}\left(\frac{x}{z}\right)$$

### Power Rule for Logarithms

We also have a rule for logarithms that deals with powers. If x and b are positive real numbers, where b ≠ 1, and if r is any real number, then:log

_{b}(x^{r}) = rlog_{b}(x)This rule allows us to take the power out of the argument. It will be multiplied by the logarithm. In other words, the logarithm of a number which is raised to a power is equal to the power multiplied by the logarithm of the number. Let's look at an example.

Example 5: Use the power rule to rewrite each logarithm

log

_{3}(x^{9})Using the power rule for logarithms, we can rewrite our logarithm:

log

_{3}(x^{9}) = 9log_{3}(x)### Special Properties of Logarithms

Lastly, we want to learn two special properties of logarithms.If b > 0 and b ≠ 1, then:

b

^{logb(x)}= xlog

_{b}(b^{x}) = xLet's look at a few examples.

Example 6: Evaluate each

log

_{11}(11^{4})Using our above rules, we can evaluate our problem as:

log

_{11}(11^{4}) = 4Example 7: Evaluate each

10

^{log10(19)}Using our above rules, we can evaluate our problem as:

10

^{log10(19)}= 19### Using the Properties of Logarithms to write alternative forms of logarithmic expressions

Now, we will put everything together and use our properties of logarithms to rewrite logarithmic expressions. Being able to apply the properties of logarithms will be important for solving equations that require logarithms. Let's look at a few examples.Example 8: Expand each logarithm

log

_{8}(x^{3}• y)^{5}Let's start by moving the exponent of 5 out in front of the logarithm:

5log

_{8}(x^{3}• y)Now, let's use our product rule for logarithms to expand:

5log

_{8}(x^{3}) + 5log_{8}(y)Lastly, we can move the exponent of 3 out in front:

(3 • 5)log

_{8}(x) + 5log_{8}(y)15log

_{8}(x) + 5log_{8}(y)Example 9: Condense each expression into a single logarithm $$log_{5}(z) + \frac{log_{5}(x)}{2} + \frac{log_{5}(y)}{2}$$ Let's rewrite division by 2 as multiplication by 1/2: $$log_{5}(z) + \frac{1}{2}log_{5}(x) + \frac{1}{2}log_{5}(y)$$ Using the power rule for logarithms, we can rewrite our problem as: $$log_{5}(z) + log_{5}(x^{ \frac{1}{2}}) + log_{5}(y^{\frac{1}{2}})$$ When we raise a number to the power of 1/2, this is the same as taking the square root of the number: $$log_{5}(z) + log_{5}(\sqrt{x}) + log_{5}(\sqrt{y})$$ Now, we can wrap up the problem by using our product rule for logarithms: $$log_{5}(z\sqrt{xy})$$

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